3c^2+18c+27=0

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Solution for 3c^2+18c+27=0 equation: 



3c^2+18c+27=0

a = 3; b = 18; c = +27;
Δ = b2-4ac
Δ = 182-4·3·27
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{-18}{6}=-3$

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